25w^2-60w+3=0

Solution for 25w^2-60w+3=0 equation:

25w^2-60w+3=0

a = 25; b = -60; c = +3;
Δ = b2-4ac
Δ = -602-4·25·3
Δ = 3300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3300}=\sqrt{100*33}=\sqrt{100}*\sqrt{33}=10\sqrt{33}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-10\sqrt{33}}{2*25}=\frac{60-10\sqrt{33}}{50}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+10\sqrt{33}}{2*25}=\frac{60+10\sqrt{33}}{50}
$